Skip Navigation

Help with a multiple simultaneous probability problem.

I can't seem to wrap my head around how to calculate this, nor the reasoning behind it.

Say you have 3 10-sided dice. 2 dice have 8 "winning" faces and 2 "losing" faces. So an 80% chance of winning. The third dice has 5 "winning" and 5 "losing" sides, so a 50% chance of winning.

If you roll all three of these dice at the same time:

-What is the probability of at least 1 dice winning.

-What is the probability of at least 2 dice winning.

-What is the probability of all 3 winning.

From what I've seen I can calculate the probability of all 3 winning by doing:

0.8 x 0.8 x 0.5=0.32

A 32% chance of all 3 winning at the same time.

But what about the others, I can't seem to figure it out.

3 comments