omg
omg
omg
If you crop the extra white space at the top, this meme has the √2̅:1 (or 2:√2̅) aspect ratio, which I find more pleasing than the "golden ratio", perhaps because I'm so used to A4 paper
x^2
—— = x
x
Proof?
ETA: Quick verification.
x² - x² = 0 and x - x = 0, then 0 = 0 and uh... again.
The other way around you get √
(I can't even draw simple stuff...)
You like installing arch don't you, you're an arch installer aren't you
Also, i use fedora
Hard to draw when you're so busy kissing boys
What if I told you that it works for any number 𝑥 you replace 2 with? (Except for 0 but still working for 𝐥𝐢𝐦 𝑥→0)
... where x is positive.
Otherwise it has an imaginary component and is complex.
Nope, it still works even then.
NOW I get it. Thanks.
Observe the identities
a / b = a × b^(-1) (A) sqrt(a) = a ^ (1/2) (B) a^b × a^c = a^(b+c) (C) (a^b)^c = a^(b × c) (D)
and derive
2 / sqrt(2) = 2 / 2^(1/2) (B) = 2 × [2^(1/2)] ^ (-1) (A) = 2 × 2^(1/2 × (-1)) (D) = 2 × 2^(-1/2) = 2 ^ [1 + (-1 / 2)] (C) = 2 ^ (1/2) = sqrt(2) (B)
It's Really simple once you get it, but it allways blows my mind.
1/sqrt(2) and 0.5 * sqrt(2) both being 0.707 always blows my mind even though it's basic algebra
This isn't intuitive to people?
2/sqrt(2) = ( sqrt(2)*sqrt(2) ) / sqrt(2)
Then cancelling out one of the sqrt(2)
s in the numerator with the sqrt(2)
in the denominator, you're left with sqrt(2)
.
I do a lot of toodling around in OpenSCAD, though, and sqrt(2)
tends to come up a lot because, you know, Pythagoras and right triangles and all that.
Also pops up a lot in basic electrical engineering as the conversion factor between amplitude and RMS value of sine waves
c/mathmemes
How am I s’posed to root two this?
(Aw, gimme somethin’ I can root two!)
i too remember when i was on 8th grade