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🦌 - 2023 DAY 2 SOLUTIONS -🦌

Day 2: Cube Conundrum


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  • Haskell

    A rather opaque parser, but much shorter than I could manage with Parsec.

    import Data.Bifunctor
    import Data.List.Split
    import Data.Map.Strict (Map)
    import qualified Data.Map.Strict as Map
    import Data.Tuple
    
    readGame :: String -> (Int, [Map String Int])
    readGame = bimap (read . drop 5) (map readPull . splitOn "; " . drop 2) . break (== ':')
      where
        readPull = Map.fromList . map (swap . bimap read tail . break (== ' ')) . splitOn ", "
    
    possibleWith limit = and . Map.intersectionWith (>=) limit
    
    main = do
      games <- map (fmap (Map.unionsWith max) . readGame) . lines <$> readFile "input02"
      let limit = Map.fromList [("red", 12), ("green", 13), ("blue", 14)]
      print $ sum $ map fst $ filter (possibleWith limit . snd) games
      print $ sum $ map (product . snd) games
    
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